If A = [4i-6 10i] [14i 6+4i] and k = 1/(2i), where i = √-1, then kA is equal to - NDA Mathematics 2017 (II)

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If A = [4i-6 10i]
[14i 6+4i] and k = 1/(2i), where i = √-1, then kA is equal to