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The line (x–1)/2 = (y–2)/–3 = (z–3)/5 is given by

Mathematics 2018 NDA Mathematics 2018 NDA 2018

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x+ y+ z = 6, x+2y–3z = –6

2x–y+z = 6, 3x–6y+5z–3 = 0

3x+2y–3z = 0, 3x–6y+5z = 3

3x+2y–3z = –2, 3x–6y+5z = 0

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